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Answer on Physical Chemistry Question for Luis Tudayan

Question #32065
The freezing point of blood serum is about - 0.56 deg C. What is its osmotic pressure at 37 deg C?
Expert's answer
Freezingpoint depression is given by:
ΔT = Kf·i·m
Kf cryoscopic constant of solvent Kf = 1.86Kkg/mol
i van't Hoff factor of solute.
m Molality = mole solute / kg solvent

Osmotic pressurie point depression is given by:
π = i·c·R·T
i van't Hoff factor of solute.
c Molarity = mole solute / m³ solution
R universal gas constant
T absolute temperature in K

Assume that
1. van't Hoff factors does not change between -0.56°C and 37°C
2. volumes of solution is equal to the volumes of solvent contained of

Then you can calculate the molarity from multiplying by pure water
c = m ·ρw
(at 37°C ρw = 994kg/m³)

Solve freezing point equation for molality
m = ΔT/(Kf·i)

c = [ΔT/( Kf·i)] · ρw

π = i · [ΔT/( Kf·i) ] ·ρw · R · T = [ΔT/Kf] ·ρw · R · T = [0.56K / 1.86Kkg/mol ] · 994kg/m³ · 8.314472J/mol K · 310K = 771361.3 Pa = 7.613atm

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Assignment Expert
07.08.2013 10:27

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Luis Tudayan
21.07.2013 10:14

thanks for the answer :>

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