Answer to Question #31856 in Physical Chemistry for manal

Question

Pure gold has a density of 119.32 g/cm3. How large would a piece of gold be if it had a mass of 3118.97 g?

Answer 1

The density of a piece of gold is its mass per unit volume.
d(Au) = m(Au) / V(Au)
The volume of the piece of gold is:
V(Au) = 3118.97 g / 119.32 g/cm³ = 26.14 cm³ (a piece of gold like a ball for ping-pong)