Answer to Question #30488 in Physical Chemistry for chad
A 6.32l football is filled with air at 1.90 atm at 25.1C at the same temperature the volume of the football is reduced to 3.49l what is the pressure of the ball in the ball?
Process, described in the problem takes place at the constant temperature, so we can use Boyle's law. According to the Boyle's law: pV = const (if the temperature is constant), where p is pressure and V is volume. This means that if volume is reduced by the factor 6.32 l / 3.49 l = 1.81, pressure will increase to this factor 1.91 atm * 1.81 = 3.46 atm