Question #26081

A gas at STP occupies 28cm^3 of space. If the pressure changes to 3.8 ATM and the temp increases at 203 degrees celcius, did the new volume. (Hint: 1cm^3 = 1 mL)

Expert's answer

STP: pressure - 10^{5} Pa = 0.98692 ATM; temperature - 0 C (273 К).

This task can be solved by such equation:

pV = nRT

V = nRT/p

All the data except T and p is constant. So if the ratio between T and p remains constant, the volume will not change.

1) 273/0.98692 = 276.6

2) (203 + 273)/3.8 = 125.26

So the volume will become less in 2.2 times: 28 ml/2 = 14 ml

This task can be solved by such equation:

pV = nRT

V = nRT/p

All the data except T and p is constant. So if the ratio between T and p remains constant, the volume will not change.

1) 273/0.98692 = 276.6

2) (203 + 273)/3.8 = 125.26

So the volume will become less in 2.2 times: 28 ml/2 = 14 ml

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