Question #25627

A sample of N2 has 1.70 moles and occupies 3.80 l at 25.0˚C.

A) What volume will it occupy with 2.60 moles?

B) How many moles are in a sample that occupies 1.45 L?

A) What volume will it occupy with 2.60 moles?

B) How many moles are in a sample that occupies 1.45 L?

Expert's answer

According to the ideal gas law:

pV=nRT

p – pressure (atm)

V – volume (L)

n – amount (moles)

R – universal gas constant

T – temperature (K)

P, R, T – don’t change, that’s why we can writea proportion

V_{1}/V_{2} = n_{1}/n_{2}

a) What volume will it occupy with 2.60 moles?

V_{2} = V_{1} x n_{2} / n_{1}

V_{2} = 3.80 x 2.60 / 1.70 = 5.81 L

Answer: V_{2} = 5.81 L

b) How many moles are in a sample that occupies 1.45 L?

n_{2} = n_{1} x V_{2} / V_{1} = 1.70 x 1.45 / 3.80 = 0.65 mol

Answer: n_{2} = 0.65 mol

pV=nRT

p – pressure (atm)

V – volume (L)

n – amount (moles)

R – universal gas constant

T – temperature (K)

P, R, T – don’t change, that’s why we can writea proportion

V

a) What volume will it occupy with 2.60 moles?

V

V

Answer: V

b) How many moles are in a sample that occupies 1.45 L?

n

Answer: n

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