Answer to Question #24863 in Physical Chemistry for zarria
where q-heat of compound, Q - heat capacity of the calorimeter, ΔT – change the temperature, m – mass of compound.
q=32.4•2.56/3.4=24.395 kJ/g=5.831 kcal/g=5831 cal/g.
Answer: The quantity of nutritional Calories per gram of the candy is 5831.
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