Answer to Question #24087 in Physical Chemistry for Morgan
The specific heat of water is 4.184 J/gxC
If there was a temperature drop in a substance, this would be heat energy "lost" in a substance.
m = m for 'mass as always, since you're trying to figure out how much heat energy that was applied, it will depend on the weight or in correct terms the "mass" of the the object.
c = basically it's a measure of how much heat energy the substance absorbs to change the temperature by 1 degree Fahrenheit/Celsius. (the unit for specific heat capacity is J kg^-1 K^-1)
Delta T = This can be the Rise in temperature or the fall in temperature!
We can use the formula:
Q = m C (T2 - T1);
Q = 250 g * 4.184 J/g*C * 20C = 20920 J or 20.92 kJ
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