Answer to Question #24087 in Physical Chemistry for Morgan
Question #24087
what amount of heat energy (in kJ) is required to warm 250g of water from 20.0 C to 40.0 C ?
The specific heat of water is 4.184 J/gxC
The specific heat of water is 4.184 J/gxC
Expert's answer
Q = Heat energy, if there was a temperature gained in a substance, this would be the heat energy "gained" in a substance.
If there was a temperature drop in a substance, this would be heat energy "lost" in a substance.
m = m for 'mass as always, since you're trying to figure out how much heat energy that was applied, it will depend on the weight or in correct terms the "mass" of the the object.
c = basically it's a measure of how much heat energy the substance absorbs to change the temperature by 1 degree Fahrenheit/Celsius. (the unit for specific heat capacity is J kg^-1 K^-1)
Delta T = This can be the Rise in temperature or the fall in temperature!
We can use the formula:
Q = m C (T2 - T1);
Q = 250 g * 4.184 J/g*C * 20C = 20920 J or 20.92 kJ
If there was a temperature drop in a substance, this would be heat energy "lost" in a substance.
m = m for 'mass as always, since you're trying to figure out how much heat energy that was applied, it will depend on the weight or in correct terms the "mass" of the the object.
c = basically it's a measure of how much heat energy the substance absorbs to change the temperature by 1 degree Fahrenheit/Celsius. (the unit for specific heat capacity is J kg^-1 K^-1)
Delta T = This can be the Rise in temperature or the fall in temperature!
We can use the formula:
Q = m C (T2 - T1);
Q = 250 g * 4.184 J/g*C * 20C = 20920 J or 20.92 kJ
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