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# Answer to Question #24087 in Physical Chemistry for Morgan

Question #24087
what amount of heat energy (in kJ) is required to warm 250g of water from 20.0 C to 40.0 C ? The specific heat of water is 4.184 J/gxC
1
2013-02-13T09:06:00-0500
Q = Heat energy, if there was a temperature gained in a substance, this would be the heat energy &quot;gained&quot; in a substance.
If there was a temperature drop in a substance, this would be heat energy &quot;lost&quot; in a substance.
m = m for &#039;mass as always, since you&#039;re trying to figure out how much heat energy that was applied, it will depend on the weight or in correct terms the &quot;mass&quot; of the the object.
c = basically it&#039;s a measure of how much heat energy the substance absorbs to change the temperature by 1 degree Fahrenheit/Celsius. (the unit for specific heat capacity is J kg^-1 K^-1)
Delta T = This can be the Rise in temperature or the fall in temperature!

We can use the formula:
Q = m C (T2 - T1);
Q = 250 g * 4.184 J/g*C * 20C = 20920 J or 20.92 kJ

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