Answer to Question #23939 in Physical Chemistry for Simon
i.e. ρ = 1.0 gcm-3 and c = 4.18 Jg-1K-1
1. Zinc will displace copper from copper (II) sulphate solution according to the following equation:
CuSO4(aq) + Zn(s) Cu(s) + ZnSO4(aq)
If an excess of zinc powder is added to 50 cm3 of 1.0 moldm-3 copper(II) sulphate, the temperature increases by 6.3 oC. Calculate the enthalpy change for the reaction.
q = 50g (from the 50cm cubed) x 4.18 x 6.3 = 1316.7 J
also, number of moles = concentration x volume divided by 1000
n = 1.0 x 50 / 1000 = 0.05 moles
so 0.05 moles = 1316.7 J
1 mole = 1316.7 divided by 0.05 = 26334 J and if we divide that by 1000 = 26.334 kJ
or q = - 26.334kJ/mol
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