Answer to Question #22977 in Physical Chemistry for Trish
Unbalanced: CH4 + O2 ---> CO2 + H2O
Balanced: CH4 + 2O2 ---> CO2 + 2H2O
X grams CH4 (Molecular mass 16.0 grams)
9 grams H2O (Molecular mass 18.0 grams)
11 grams CO2 (Molecular mass 44.0 grams)
Mole ratio: 1:2:1:2 (CH4:O2:CO2:H2O)
Then you need to find which of the reactants are the limiting reactant and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.
11 g CO2 / (44.0 g) = 0.25 moles CO2
9 g H2O / (18.0 g) = 0.5 moles
n of CH4 = n of CO2 = n of H2O /2 = 0.25 moles
m of CH4 = n* Mw = 0.25 * 16.0 = 4 g
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