Answer to Question #22695 in Physical Chemistry for Bulbul

Question

How moles of oxygen are there in 50L tank at 21 c when the oxygen pressure is 15.7atm?

Answer 1

pV = nRT
, where P is the pressure of the gas, V is the volume of the gas, n is the amount of substance of gas (also known as number of moles), T is the temperature of the gas and R is the ideal, or universal, gas constant , equal to the product of Boltzmann's constant and Avogadro's constant. Hence,
n = pV/RT
p = 15.7 atm
1 atm = 1.013 * 10^5 Pa
p = 15.7*1.013 *10^5 = 1.59 * 10^6 Pa
V = 50 * 10^-3 m³
T = 294 K
R = 8.314 J/mol*K
n = (1.59 * 10^6 Pa * 50 * 10^-3 m3)/(8.314 J/mol*K * 294K) = 35.52 mol
Answer:
n(H₂) = 32.52 mol