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Answer to Question #21804 in Physical Chemistry for Kanesha Mcbride

Question #21804
Ammonia combines with acids in the presence of water to produce salt.
NH3(g) + HCI(aq) ----> NH4CI(aq)
If 45 grams of NH3 are used with an excess of HCI, how much grams of ammonia chloride will be produced?
A.45g
B.33.8g
C.141.5g
D.2.65g
Expert's answer
First of all you have to find amounts in mol of all known components of reaction:

HCl - excess

NH3 45 g

n of NH3 = m/Mw = 45 / 17 = 2.647 mol

NH3(g) + HCI(aq) ----> NH4CI(aq)

the ratio between NH3 : NH4CI = 1:1, so amount
of NH4CI is 2.647 mol

Now you can find mass of NH4CI

m = n*Mw = 2.647*53.5 = 141.5g

So the answer is C = 141.5g

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