Answer to Question #21804 in Physical Chemistry for Kanesha Mcbride

Question #21804
Ammonia combines with acids in the presence of water to produce salt.
NH3(g) + HCI(aq) ----> NH4CI(aq)
If 45 grams of NH3 are used with an excess of HCI, how much grams of ammonia chloride will be produced?
A.45g
B.33.8g
C.141.5g
D.2.65g
1
Expert's answer
2013-01-28T09:59:56-0500
First of all you have to find amounts in mol of all known components of reaction:

HCl - excess

NH3 45 g

n of NH3 = m/Mw = 45 / 17 = 2.647 mol

NH3(g) + HCI(aq) ----> NH4CI(aq)

the ratio between NH3 : NH4CI = 1:1, so amount
of NH4CI is 2.647 mol

Now you can find mass of NH4CI

m = n*Mw = 2.647*53.5 = 141.5g

So the answer is C = 141.5g

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