Answer to Question #201041 in Physical Chemistry for Piyush Bhatt

Question

The enthalpy of formation of NH3(g) as per the following reaction is -46.11 kJ/mol at 298 K.

N2(g) + 3H2(g) 2 NH3(g) 

Calculate the value of enthalpy of formation of NH3(g) at 100 oC. The Cp values are given as: N2(g) = 29.12; H2(g) = 28.82; NH3(g) = 35.06. Assume the given heat capacity values to be temperature independent in the range. 

Answer 1

Enthalpy of formation of NH3=$−46.1 kJ/mol$