# Answer on Physical Chemistry Question for Brianna Dunmore

Question #19788

What is the density of propene gas measured at pressure of 0.5 atm and temperature of 470C?

Expert's answer

470 C = 273 + 470 K = 743 K

first we find concentration of the propene:

p = nkT

n = p/Tk = 0.5* 101.3*10

49.4*10^(23) molecules/ m^3

now to find density

ho = n* (mass of molecule) = 49.4*10^(23) * (42.08*1.a.m.u) = 49.4*10^(23) * 42.08* 1.660*10^(-27) = 0.345 kg/m^3

density of propene is 0.345 kg/m^3

first we find concentration of the propene:

p = nkT

n = p/Tk = 0.5* 101.3*10

^{3}Pa/ (743 K 1.38*10^(-23)m^2 s^(-2)*K^(-1)) =49.4*10^(23) molecules/ m^3

now to find density

ho = n* (mass of molecule) = 49.4*10^(23) * (42.08*1.a.m.u) = 49.4*10^(23) * 42.08* 1.660*10^(-27) = 0.345 kg/m^3

density of propene is 0.345 kg/m^3

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