Answer to Question #16281 in Physical Chemistry for hunter hughes
(a) How many moles of AgCl would precipitate?
x & in& 32.9& mL
x=0.479*32.9/1000=0.01576 mol of NaCl
0.331 mol in 1000 ml
y & in& 32.9
y=0.0109 mol of AgNO3&
NaCl is in excess
NaCl+AgNO3---->NaNO3 + AgCl
It means that 0.0109 mol of AgNO3 can form 0.0109 mol& AgCl
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