Question #15886

What is the specific heat of a substance if 19.5 kJ are required to raise the temperature of 205 g of the substance from 56.5°C to 197.0°C?

Expert's answer

Q=m*c*(t2-t1)

c=Q/(m*(t2-t1))=19.5 kJ / (0.205 kg *(197-56.5)K) = 0.677

kJ/(kg*K)

c=Q/(m*(t2-t1))=19.5 kJ / (0.205 kg *(197-56.5)K) = 0.677

kJ/(kg*K)

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