Question #15634

A vessel contains 12 gm of an ideal gas at 1 degree Celsius and 1 atm pressure.When the temp is increased by 10 degree Celsius at the same volume,the pressure increases by 10%.calculate the volume and initial temp.

Expert's answer

m(gas) = 12 g

t1(gas) = 1 deg C

p1(gas) = 1 atm

t2(gas) = 10 deg

C

V(gas) = const

p2(gas) = 1.1 atm

Calculate:

V(gas) -

?

t1(gas) - ?

pV = nRT

p1 * V1 * T2 = p2 * V2 *T1

V1 = V2

p1

* t2 = p2 * t1

t1 = initial temperature = 1 deg C

This assignment

cannot be solved due to incorrect data (the mass for ideal gas).

If we

suppose the amount of ideal gas 12 mol, the assignment can be

solved:

pV=nRT

V = nRT/p = 12 mol * 0.082 L*atm*K(-1)*mol(-1) * 274 K / 1

atm = 269.6 L

Answer:

Initial temperature: 274 K

Volume: 269.6 L

t1(gas) = 1 deg C

p1(gas) = 1 atm

t2(gas) = 10 deg

C

V(gas) = const

p2(gas) = 1.1 atm

Calculate:

V(gas) -

?

t1(gas) - ?

pV = nRT

p1 * V1 * T2 = p2 * V2 *T1

V1 = V2

p1

* t2 = p2 * t1

t1 = initial temperature = 1 deg C

This assignment

cannot be solved due to incorrect data (the mass for ideal gas).

If we

suppose the amount of ideal gas 12 mol, the assignment can be

solved:

pV=nRT

V = nRT/p = 12 mol * 0.082 L*atm*K(-1)*mol(-1) * 274 K / 1

atm = 269.6 L

Answer:

Initial temperature: 274 K

Volume: 269.6 L

## Comments

## Leave a comment