Answer to Question #155033 in Physical Chemistry for Kathryn

Question

A gas has a volume of 2.8 L at a temperature of 27°C. What temperature (°C) is needed to expand the volume to 15 L?

Answer 1

Temperature should be in Kelvin for calculations: 27^oC = 300 K.

According to the Charles' law,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Therefore,

$T_2=\frac{T_1V_2}{V_1}=\frac{300K\times15L}{2.8L}=1607K=1334^\circ{C}$ (1300^oC to 2 significant digits)

Answer: 1300^oC