Answer to Question #15087 in Physical Chemistry for Chad Benjamin

Question

(5a) Suppose you obtained an experimental (actual) yield of 1.81g of Aspirin and the theretically expected yield was 2.14 g. What is the % yield of Aspirin?

(5b) If your aspirin above was contaminated with 16.1% of salicylic acid, what is the correct experimental yield?

(5c) What is the correct % yield?

Answer 1

For pure aspirin:
yield,% = 1.81/2.14 = 0.846 or 84.6%
For contaminated
aspirin:
yield = 1.81*(1-0.161)=1.52 g
yield,% = 1.52/2.14 = 0.710 or
71.0%