# Answer on Physical Chemistry Question for Chesca Mae

Question #13922

Calculate the change in entropy when argon at 25 degree Celcius and 1.00 bar in a container of volume 0.500 dm^3 is compressed to 0.500 dm^3 and cooled to 25 degree Celcius.

Expert's answer

Assuming ideal gas:

delta_S = n * C

argon molar heat capacity is 20.786 J·mol

delta_S = 1* 20.768* ln (1) + 1*8.31*ln (1) = 0 + 0 =0

delta_S = n * C

_{v}* ln(T_{f}/ T_{i}) + n * R * ln(V_{f }/ V_{i})argon molar heat capacity is 20.786 J·mol

^{−1}·K^{−}"when argon at 25 degree Celcius" and "oled to 25 degree Celcius" means that T is constant,the same with volumedelta_S = 1* 20.768* ln (1) + 1*8.31*ln (1) = 0 + 0 =0

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment