Calculate the change in entropy when argon at 25 degree Celcius and 1.00 bar in a container of volume 0.500 dm^3 is compressed to 0.500 dm^3 and cooled to 25 degree Celcius.
Assuming ideal gas: delta_S = n * Cv * ln(Tf / Ti) + n * R * ln(Vf / Vi) argon molar heat capacity is 20.786 J·mol−1·K− "when argon at 25 degree Celcius" and "oled to 25 degree Celcius" means that T is constant,the same with volume delta_S = 1* 20.768* ln (1) + 1*8.31*ln (1) = 0 + 0 =0
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