Question #13922

Calculate the change in entropy when argon at 25 degree Celcius and 1.00 bar in a container of volume 0.500 dm^3 is compressed to 0.500 dm^3 and cooled to 25 degree Celcius.

Expert's answer

Assuming ideal gas:

delta_S = n * C_{v} * ln(T_{f} / T_{i}) + n * R * ln(V_{f }/ V_{i})

argon molar heat capacity is 20.786 J·mol^{−1}·K^{−}"when argon at 25 degree Celcius" and "oled to 25 degree Celcius" means that T is constant,the same with volume

delta_S = 1* 20.768* ln (1) + 1*8.31*ln (1) = 0 + 0 =0

delta_S = n * C

argon molar heat capacity is 20.786 J·mol

delta_S = 1* 20.768* ln (1) + 1*8.31*ln (1) = 0 + 0 =0

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