Answer to Question #116439 in Physical Chemistry for Himanshu katara

Question

PA°equal to 200 torr and PB°equals to 100 torr calculate the composition of vapour of liquid solution containing A and B at 50 degree centigrade is the normal boiling point of solution?

Answer 1

Solution.

$P = P^0(A) + P^0(B)$

P = 300 torr

$\chi(A) = \frac{P^0(A)}{P} = 0.67$

$\chi(B) = \frac{P^0(B)}{P} =0.33$

$t = \chi(a) \times P^0(A) + \chi(B) \times P^0(B)$

$t = 0.67 \times 200 + 0.33 \times 100 = 167 \ K$

50 is not a normal boiling point.

Answer:

$\chi(A) = \frac{P^0(A)}{P} = 0.67$

$\chi(B) = \frac{P^0(B)}{P} =0.33$

50 is not a normal boiling point.