Question #10987

if a gas exerts a pressure of 102.5 kPa at 25 Kelvin, what is its pressure at a temperature of -100,0C?

Expert's answer

The temperature in Kelvin`s is T2 = 273 - 100 = 173 K

P1/T1 = P2/T2

P2 =

P1 * T2 / T1 = 102.5 * 173 / 25 = 709.3 kPa

P1/T1 = P2/T2

P2 =

P1 * T2 / T1 = 102.5 * 173 / 25 = 709.3 kPa

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