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Answer to Question #10240 in Physical Chemistry for david
Question #10240
a 26% aqueous solution of sulfuric acid has a density of 1.129 at 20 degrees celcius. calculate the molarity and molality
Expert's answer
Molarity
C(H2SO4) = n(H2SO4)/V(solution) = d(H2SO4)*w(H2SO4)/M(H2SO4) =
1.129*0.26/98 = 0.003 mol/L = 3 mM
Molality
b(H2SO4) =
n(solute)/m(solvent) = w/((1-w)*M) = 0.26/(0.74*98) = 0.0036
C(H2SO4) = n(H2SO4)/V(solution) = d(H2SO4)*w(H2SO4)/M(H2SO4) =
1.129*0.26/98 = 0.003 mol/L = 3 mM
Molality
b(H2SO4) =
n(solute)/m(solvent) = w/((1-w)*M) = 0.26/(0.74*98) = 0.0036
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