Answer to Question #7060 in Other Chemistry for Emily

Question #7060
I need 100 mL of a buffer with a pH of 5.20 and it's acetic acid or HC2H3O2. So I need to find out how many grams of acetic acid are needed to make this buffer. (Ka = 1.8 x 10-5) What I have so far... pH = pKa + log(base/acid) 5.20 = 4.74 + logx x = 2.884 M 2.884 M * .1 L = .2884 mol .2884 mol * 60.052 g = 17.32 g i know this is wrong because the answer is 11.54 g. can you help me find my mistake please?
1
Expert's answer

Not answered

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal