# Answer to Question #52398 in Other Chemistry for CeeCee

Question #52398

A piece of wood from an archeological site has a carbon-14/carbon-12 ratio that is

12.5% that of the carbon-14/carbon-12 ratio in living materials. How old is the wood

from the temple site? The half â€“life of C-14 is 5,730 years.

12.5% that of the carbon-14/carbon-12 ratio in living materials. How old is the wood

from the temple site? The half â€“life of C-14 is 5,730 years.

Expert's answer

Carbon-14/carbon-12 ratio at the moment when organism die is the same as every other living thing.

Carbon-14 decays and is not replaced.

Carbon-14 decays with its half-life of 5,730 years. At the same time the amount of carbon-12 remains constant in the sample.

By looking at the carbon-14/carbon-12 in the sample and comparing it to the ratio in a living organism, it is possible to determine the age of a remain.

To calculate how old a sample is by carbon-14 dating, we must use a formula:

t = [ ln (Nf/No) / (-0.693) ] x t1/2

where: Nf/No is the percent of carbon-14 in the sample compared to the amount in living tissue; t1/2 is the half-life of carbon-14.

t = [ ln 0.125 / (-0.693) ] x 5,730=17,104 years

Carbon-14 decays and is not replaced.

Carbon-14 decays with its half-life of 5,730 years. At the same time the amount of carbon-12 remains constant in the sample.

By looking at the carbon-14/carbon-12 in the sample and comparing it to the ratio in a living organism, it is possible to determine the age of a remain.

To calculate how old a sample is by carbon-14 dating, we must use a formula:

t = [ ln (Nf/No) / (-0.693) ] x t1/2

where: Nf/No is the percent of carbon-14 in the sample compared to the amount in living tissue; t1/2 is the half-life of carbon-14.

t = [ ln 0.125 / (-0.693) ] x 5,730=17,104 years

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment