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Answer to Question #50359 in Other Chemistry for Meagan

Question #50359
When 75.0 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?

6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g
Expert's answer
From the equation
6O2 + C6H12O6 -> 6H2O +6CO2
one can see that there isproduced as much moles of CO2 as moles of O2 reacted, andsince both are gases their volumes are equal as well.
Since 6H2O is inexcess all given O2 will react, i.e. 75 dm­­3.
Therefore, 75 dm3 of CO2will be produced.

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