Answer to Question #50359 in Other Chemistry for Meagan
When 75.0 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?
6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g
From the equation 6O2 + C6H12O6 -> 6H2O +6CO2 one can see that there isproduced as much moles of CO2 as moles of O2 reacted, andsince both are gases their volumes are equal as well. Since 6H2O is inexcess all given O2 will react, i.e. 75 dm­­3. Therefore, 75 dm3 of CO2will be produced.