Answer to Question #50359 in Other Chemistry for Meagan
6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g
6O2 + C6H12O6 -> 6H2O +6CO2
one can see that there isproduced as much moles of CO2 as moles of O2 reacted, andsince both are gases their volumes are equal as well.
Since 6H2O is inexcess all given O2 will react, i.e. 75 dm­­3.
Therefore, 75 dm3 of CO2will be produced.
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