Answer to Question #50359 in Chemistry for Meagan

Question

When 75.0 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?

6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g

Answer 1

From the equation
6O₂ + C₆H₁₂O₆ -> 6H₂O +6CO₂
one can see that there isproduced as much moles of CO₂ as moles of O₂ reacted, andsince both are gases their volumes are equal as well.
Since 6H₂O is inexcess all given O₂ will react, i.e. 75 dm­­³.
Therefore, 75 dm³ of CO₂will be produced.