Answer to Question #49840 in Other Chemistry for jessica
68 kcal + O2(g) <-> O3(g) + 31 kcal
3*68 kcal +3 O2(g) <-> 2 O3(g) + 2*31 kcal
After simplifying we obtain the final result:
3 O2(g)<-> 2 O3(g) - 142 kcal
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