Answer to Question #48985 in Other Chemistry for Aidee
The equation of this reaction is:
Suppose that x is number of grams of C12H22O11.
The molar mass of 6CO2is 264g/mole.
So, we get x/342 =2.90/264, x= (2.90*342)/264 = 3.76g.
The mass percentage of C12H22011 is (3.76/5.50)*100%=68.36%
The mass percentage of salt is 100% - 68.36% =31.64%
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