Question #48985

Table salt and sugar are accidently mixed 5.50g sample is burned and a 2.90g of co2 is produced what is the mass percentage

Expert's answer

Only sugar takes partin this burning reaction. The molecular formula of sugar is C12H22011, so, the molar mass of sugar is 342g/mole.

The equation of this reaction is:

C12H22011+6O2=6CO2+11H2O

Suppose that x is number of grams of C12H22O11.

The molar mass of 6CO2is 264g/mole.

So, we get x/342 =2.90/264, x= (2.90*342)/264 = 3.76g.

The mass percentage of C12H22011 is (3.76/5.50)*100%=68.36%

The mass percentage of salt is 100% - 68.36% =31.64%

The equation of this reaction is:

C12H22011+6O2=6CO2+11H2O

Suppose that x is number of grams of C12H22O11.

The molar mass of 6CO2is 264g/mole.

So, we get x/342 =2.90/264, x= (2.90*342)/264 = 3.76g.

The mass percentage of C12H22011 is (3.76/5.50)*100%=68.36%

The mass percentage of salt is 100% - 68.36% =31.64%

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