Question #35639

If 33.0 L of a gas is collected at 23 °C and 255 kPa, what is its volume at STP?

Expert's answer

First, let's use the Mendeleev-Clapeyron law to determine the quantity of matter of the gas:

PV=nRT; n=(PV)/RT=(255*10^3*33*10^-3)/(296*8.31)=3.42 mol

Each mole of the gas at standard conditions possesses a volume of 22.4 L, therefore;

V=22.4*3,42=76.51 L

PV=nRT; n=(PV)/RT=(255*10^3*33*10^-3)/(296*8.31)=3.42 mol

Each mole of the gas at standard conditions possesses a volume of 22.4 L, therefore;

V=22.4*3,42=76.51 L

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