Answer to Question #35637 in Other Chemistry for sousou
Then, let's write down to equations for combustion of gases:
Let's solve the system of 2 equations with 2 unknown. We indicate number of moles of methane as x, and number of moles of propane as y.
Thus, the molar fraction of methane would be 0.15/0.225=0.(6) and the fraction of propane is 0.(3)
The mixture of initial gas consists of 66.6% of methane and 33.3% of propane
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