Question #33358

A sample of hydrated Barium Chloride, BCl2 x H2O weighed 428.3mg before and 356.2mg after heating as BaCl2. What is the average number of water of hydration per molecules of BaCl2?(what is the X in BaCl2 X H20?

Expert's answer

We can find the mass of water in BaCl_{2}*xH_{2}O:

428.3 - 356.2 = 72.1

The molar mass of water is 18. So, we find the number of molecules of water: 72.1/18 = 4

428.3 - 356.2 = 72.1

The molar mass of water is 18. So, we find the number of molecules of water: 72.1/18 = 4

## Comments

## Leave a comment