Answer to Question #30682 in Other Chemistry for Kel
N2 (g) + 3H2 (g)------> 2NH3 (g)
n = m/M
where n - amount of moles
m - mass
M - molar mass
n(N2) = 84/24 = 3.5 moles
n(H2) = 3*n(N2) = 3*3.5 = 10.5 moles
So the needed amount of H2 is 10.5 moles. The real amount of H2 in 12 grams is:
n(H2) = 12/1 = 12 moles
The needed amount of H2 is greater than the real one. So the amount of this element is limiting.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!