What is the final volume in milliliters when 0.952L of a 42.3\% (m/v) solution is diluted to 20.2\% (m/v)?
If 0.952 L contain 42.3% (m/v): x/0.952 = 0.423. The mass of a dissolved substance is: 0.423 x 0.952 = 0.403 grams. So if the original amount of a solution is being diluted to 20.2%, the mass of a dissolved substance remains the same. 0.403/x = 0.202 x = 0.403/0.202 = 1.99 That is why the final amount of a solution 20.2% (m/v) is 1.99 L.
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