Question #28176

What is the final volume in milliliters when 0.952L of a 42.3\% (m/v) solution is diluted to 20.2\% (m/v)?

Expert's answer

If 0.952 L contain 42.3% (m/v):

x/0.952 = 0.423.

The mass of a dissolved substance is: 0.423 x 0.952 = 0.403 grams.

So if the original amount of a solution is being diluted to 20.2%, the mass of

a dissolved substance remains the same.

0.403/x = 0.202

x = 0.403/0.202 = 1.99

That is why the final amount of a solution 20.2% (m/v) is 1.99 L.

x/0.952 = 0.423.

The mass of a dissolved substance is: 0.423 x 0.952 = 0.403 grams.

So if the original amount of a solution is being diluted to 20.2%, the mass of

a dissolved substance remains the same.

0.403/x = 0.202

x = 0.403/0.202 = 1.99

That is why the final amount of a solution 20.2% (m/v) is 1.99 L.

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