76 778
Assignments Done
Successfully Done
In June 2019

Answer to Question #26148 in Other Chemistry for MICHAEL VINCE PADILLA

Question #26148
A 25.0 mL sample of HCL was titrated to the endpoint with 15.0 mL of 2.0 N NaOH.What was the normality of the HCL?What was its molarity
Expert's answer
The chemical equation is
NaOH + HCl = NaCl + H2O

According to the equation the amount of NaOH = the amount of HCl
That's why we can write the equation

C(NaOH) x V(NaOH) = C(HCl) x V(HCl)
C(HCl) = C(NaOH) x V(NaOH)/V(HCl) = 2.0 x 15.0 / 25.0 = 1.2 N

For the acids that have only one hydrogen atom the molarity = normality

The normality of HCl = 1.2 N
The molarity of HCl = 1.02 M

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions