# Answer to Question #26136 in Other Chemistry for Carry lols

Question #26136
Consider the following reaction. C6H12O6 + 6O2 =&gt; 6CO2 + 6H2O This equation shows the overall reaction of the process of respiration, which is the set of chemical reactions that give energy to the majority of non-plant life on earth. If I have 15 moles of oxygen and 7 moles of glucose (C6H12O6) which one will be the limiting reagent and how much carbon dioxide (CO2) will be produced?
According to the equation n(C6H12O6) = 6 x n(O2)
If we have 7 moles of glucose there have to be 6 x 7 = 42 moles of O2, but we have only 15 moles of O2. The limiting reagent is the reagent which amount is not enought to complete the reaction. In our case it&#039;s O2
The amount of CO2 is
n(CO2) = n(O2) = 15 moles

Answer: The limiting reagent is O2

There will be 15 moles of CO2 produced.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!