Answer to Question #26136 in Chemistry for Carry lols

Question

Consider the following reaction.
C6H12O6 + 6O2 => 6CO2 + 6H2O

This equation shows the overall reaction of the process of respiration, which is the set of chemical reactions that give energy to the majority of non-plant life on earth.

If I have 15 moles of oxygen and 7 moles of glucose (C6H12O6) which one will be the limiting reagent and how much carbon dioxide (CO2) will be produced?

Answer 1

According to the equation n(C₆H₁₂O₆) = 6 x n(O₂)
If we have 7 moles of glucose there have to be 6 x 7 = 42 moles of O₂, but we have only 15 moles of O₂. The limiting reagent is the reagent which amount is not enought to complete the reaction. In our case it's O₂
The amount of CO₂ is
n(CO₂) = n(O₂) = 15 moles

Answer: The limiting reagent is O₂

There will be 15 moles of CO₂ produced.