How many moles of HF are required to dissolve 6.9 moles of sodium dilicate in this reaction?
To answer this question we are to write down the reaction and to put the coefficients: 2HF+Na2SiO3=2NaF+H2SiO3 So we can see that the amount of HF is two times more than Na2SiO3. If we have 6.9 moles of sodium silicate the amount of HF is: 6.9 /2=3,45 moles
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