Question #24948

How many moles of HF are required to dissolve 6.9 moles of sodium dilicate in this reaction?

Expert's answer

To answer this question we are to write down the reaction and to put the coefficients:

2HF+Na2SiO3=2NaF+H2SiO3

So we can see that the amount of HF is two times more than Na2SiO3.

If we have 6.9 moles of sodium silicate the amount of HF is: 6.9 /2=3,45 moles

2HF+Na2SiO3=2NaF+H2SiO3

So we can see that the amount of HF is two times more than Na2SiO3.

If we have 6.9 moles of sodium silicate the amount of HF is: 6.9 /2=3,45 moles

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