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Answer to Question #24942 in Chemistry for jordan taylor
Question #24942
find the percentage of water (to the nearest tenth) in a crystal of cuso4 x 5h2o
Expert's answer
Percentage of water is next:
w of H2O = 5 * Mw of H2O / Mw CuSO4*5H2O
Mw is molecular mass:
Mw(H2O) = 18 = 90
Mw(CuSO4*5H2O) = 160 + 90 = 250
w of H2O = 90/250*100% = 36 %
w of H2O = 5 * Mw of H2O / Mw CuSO4*5H2O
Mw is molecular mass:
Mw(H2O) = 18 = 90
Mw(CuSO4*5H2O) = 160 + 90 = 250
w of H2O = 90/250*100% = 36 %
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