Answer to Question #22142 in Chemistry for Adlyn Elliston

Question #22142

what is the molar mass of the solid acid HX, if 0.489 g of the acid is neutralized by 39.63 ml of 0.250 m naoh?

Expert's answer

The reaction between acid HX and NaOH:

NaOH + HX = NaX + H₂O

n of NaOH = V*C/1000 = 39.63*0.250 / 1000 = 0.00991 mol

M_w = m/n = 0.489/0.00991 = 49

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. Calculate the grams of oxygen produced if 16.0 grams of lithium chlorate are completely decomposed b
2. If 25 mL of an acid is mixed with 25 mL of base what can you say about the concentration of the base
3. Avogardos number was calculated as the number of what?
4. Calculate the pH of the solution obtained by adding 0.02 lit of 1 mol./lit nitrous acid (pKa=3.34) t
5. t-test or student's - t & chisquare test
6. Determination of ph of acid solution like o.1M Hcl,0.05M Hcl and 0.0125M Hcl by using quinhydrone an
7. why do we find it useful to have two units for the amount of substance , the kilogram and mole ?