Answer to Question #22142 in Chemistry for Adlyn Elliston
what is the molar mass of the solid acid HX, if 0.489 g of the acid is neutralized by 39.63 ml of 0.250 m naoh?
The reaction between acid HX and NaOH:
NaOH + HX = NaX + H2O
n of NaOH = V*C/1000 = 39.63*0.250 / 1000 = 0.00991 mol
Mw = m/n = 0.489/0.00991 = 49
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