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Answer to Question #22142 in Other Chemistry for Adlyn Elliston

Question #22142
what is the molar mass of the solid acid HX, if 0.489 g of the acid is neutralized by 39.63 ml of 0.250 m naoh?
Expert's answer
The reaction between acid HX and NaOH:

NaOH + HX = NaX + H2O

n of NaOH = V*C/1000 = 39.63*0.250 / 1000 = 0.00991 mol

Mw = m/n = 0.489/0.00991 = 49

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