Question #20808

If 5 grams of nitrogen is oxidized in air, then what is the empirical formula of compound, if it's mass is 19.3 grams?

Expert's answer

General equation for this process is next:

N_{2} + xO_{2} = 2NO_{x}

let's find x

5 19.3

N_{2} + xO_{2} = 2NO_{x}

28 2(14+16x)

2(14 + 16x)*5 = 28* 19.3

2(14 + 16x)*5 = 540.4

14 + 16x = 54.04

16x = 40

x = 2.5

so empiric formula is NO_{2.5}, or N_{2}O_{5}

N

let's find x

5 19.3

N

28 2(14+16x)

2(14 + 16x)*5 = 28* 19.3

2(14 + 16x)*5 = 540.4

14 + 16x = 54.04

16x = 40

x = 2.5

so empiric formula is NO

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