Answer to Question #20619 in Other Chemistry for jasie
a) What is the initial molarity of potassium chromate in the solution? b) What mass of potassium
is present in solution? Write the formula for the precipitate that forms. Assume a final volume
of 75.0 mL.
K2CrO4 + Mg(NO3)2 = MgCrO4 (precipitate) + 2KNO3
The amount of Mg(NO3)2 is : 75.0*0.250/1000 = 0.01875 mol
The amount of K2CrO4 = 3.5/194 = 0.01804 mol
Mg(NO3)2 is in excess and it means that there is no K2CrO4 in solution after and initial molarity of potassium chromate in the solution = 0
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