What is the molarity of of 485.0g of Na2CO3 dissolved in 2.5 L of water?
The molar mass of Na2CO3 is 106 g/mol.
(485.0 g Na2CO3) × (1 mol Na2CO3 / 106 g Na2CO3) = 4.575 mol Na2CO3
Molarity = Moles of solute / Volume of solution
Molarity of Na2CO3 = (4.575 mol) / (2.5 L) = 1.83 mol/L = 1.83 M
Molarity of Na2CO3 = 1.83 M
Answer: 1.83 M is the molarity of Na2CO3.