Answer to Question #205603 in Chemistry for marianna

Question

What is the molarity of of 485.0g of Na2CO3 dissolved in 2.5 L of water?

Answer 1

Solution:

The molar mass of Na₂CO₃ is 106 g/mol.

Therefore,

(485.0 g Na₂CO₃) × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 4.575 mol Na₂CO₃

Molarity = Moles of solute / Volume of solution

Molarity of Na₂CO₃ = (4.575 mol) / (2.5 L) = 1.83 mol/L = 1.83 M

Molarity of Na₂CO₃ = 1.83 M

Answer: 1.83 M is the molarity of Na₂CO₃.