Answer to Question #205236 in Chemistry for Bob

Question #205236

Silver sulfide and hydrogen gas combine to form silver and hydrogen sulfide. 3.0 g of H2 and 100 g of Ag2S are used to produce silver. The equation for the reaction is:

 Ag2S + H2 -> 2Ag + H2S

Calculate the theoretical yield of silver? Your answer needs to explain what is the limiting reagent.

Expert's answer

According to the reaction one mole of hydrogen reacts with one mole of silver sulfide. The number of moles of reactants used in the reaction are:

n(H2) = m(H2) / Mr(H2) = 3.0 g / 2 g/mol = 1.5 mol

n(Ag2S) = m(Ag2S) / Mr(Ag2S) = 100 g / 248 g/mol = 0.4 mol

Since the reaction occurs between 0.4 mol of Ag2S and 1.5 mol of H2, Ag2S is a limiting reactant. From here, the theoretical yield of silver equals:

m(Ag) = m(Ag2S) × Mr(Ag) × 2 / Mr(Ag2S) = 100 g × 108 g/mol × 2 / 248 g/mol = 87.1 g

Answer: 87.1 g

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be the first!

Leave a comment

Ask Your question

New on Blog