Answer to Question #204296 in Chemistry for Asia

Question

How many grams of oxygen are required to burn 13.50 grams of acetylene, C2H2

Answer 1

2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O

n (O₂) = 5/2 x n (C₂H₂)

n = m / M

M (O₂) = 16 g/mol

M (C₂H₂) = 26.04 g/mol

n (C₂H₂) = 13.50 / 26.04 = 0.52 mol

n (O₂) = 5/2 x 0.52 = 1.3 mol

m (O₂) = 1.3 x 16 = 20.8 g