Answer to Question #202598 in Chemistry for kim

Question #202598

1.   Ten grams of plastic beads with a density of 1.2 g/cm3 are added to 500 ml of an organic solvent with a density of 0.80 g/cm3. What is the concentration of plastic beads in mg/L?



1
Expert's answer
2021-06-04T09:54:03-0400

Solution:

Mass of plastic beads = 10 g

Volume of plasctic beads = (10 g) / (1.2 g cm-3) = 8.33 cm3 = 8.33 mL

Volume of organic solvent = 500 mL

Volume of solution = 8.33 mL + 500 mL = 508.33 mL = 0.50833 L = 0.508 L

Therefore,

Concentration of plastic beads = (10 g) × (1000 mg / 1 g) × (1 / 0.508 L) = 19685 mg/L

Concentration of plastic beads = 19685 mg/L


Answer: The concentration of plastic beads is 19685 mg/L.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS