NaCl + H2SO4 —> NaHSO4 + HCl If a reaction vessel contains 10.0 g of sodium chloride and 12.0 g of sulfuric acid, what is the limiting reactant?
NaCl + H2SO4 —> NaHSO4 + HCl
n = m / M
M (NaCl) = 58.4 g/mol
M (H2SO4) = 98.1 g/mol
n (NaCl) = 10 / 58.4 = 0.17 mol
n (H2SO4) = 12 / 98.1 = 0.12 mol
According to the equation, n(NaCl) = n(H2SO4). From the given reactant amounts, H2SO4 is the limiting reactant.