Answer to Question #199120 in Chemistry for Jordan

Question #199120

2. Sodium metal reacts with water to form sodium hydroxide and hydrogen gas


a. Balanced Chemical Reaction:


 b. If you have 90.0 g of sodium and 80.0 g of water which is the limiting reactant and which is the excess reactant?


c. How many grams of the excess reactant are left over when the reaction is completed?


d. How many grams of hydrogen gas are produced?


1
Expert's answer
2021-05-31T02:38:55-0400

1) 2Na + 2H2O = 2NaOH + H2


2) n = m / M

M (Na) = 23 g/mol

M (H2O) = 18 g/mol

M (H2) = 2 g/mol

n (Na) = 90 / 23 = 3.9 mol

n (H2O) = 80 / 18 = 4.4 mol

According to the equation n (Na) = n (H2O).

With the given amont of reactants Na is the limiting reactant.


3) The excess amount of H2O is: 4.4 - 3.9 = 0.5 mol.

m (H2O) = n x M = 0.5 x 18 = 9 g


4) According to the eqation, n (H2) = 1/2 x n (Na) = 3.9 / 2 = 1.95 mol

m (H2) = n x M = 1.95 x 2 = 3.9 g



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS