Answer to Question #197761 in Chemistry for POGI

Question #197761

Suppose you had 58.44 g of NaCl and you dissolved it in exactly 2.00 L of water. What would be the molality?


1
Expert's answer
2021-05-24T07:26:29-0400

The molality can be calculated using the following equation:

M = n(solute)/m(solvent)

where n - moles of solute, m mass of solvent (kg)

n(NaCl) = m(NaCl) / Mr(NaCl) = 58.44 g / 58.44 g/mol = 1 mol

From here, the molality of the solution is:

M(NaCl) = n(NaCl) / m(H2O) = 1 mol / 2 kg = 0.5 mol/kg


Answer: 0.5 mol/kg

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS