Answer to Question #197523 in Chemistry for Andu

Question

16. Calculate the number of moles for 11.2 liters of fluorine, F2 (in K.N.) and for 35.5 g of chlorine, Cl2 (Ar = 35.5)

Answer 1

Solution:

At STP, one mole of any gas occupies a volume of 22.4 L.

Thus, (11.2 L F₂) × (1 mol / 22.4 L) = 0.5 mol F₂

Moles of fluorine gas (F₂) = 0.5 mol

The molar mass of Cl₂ is 2 × Ar(Cl) = 2 × 35.5 = 71 g/mol.

Thus, (35.5 g Cl₂) × (1 mol Cl₂ / 71 g Cl₂) = 0.5 mol Cl₂

Moles of chlorine gas (Cl₂) = 0.5 mol

Answer:

Moles of fluorine gas (F₂) = 0.5 mol

Moles of chlorine gas (Cl₂) = 0.5 mol