Answer to Question #195844 in Chemistry for Nazareth

Question

If 5 moles of N₂ reacted with 12 moles of O₂ according to 0 N2 + 2 O₂ + NO₂ how many moles NO₂ are produced

Answer 1

Solution:

Balanced chemical equation:

N₂ + 2O₂ → 2NO₂

According to the equation above: 2×n(N₂) = n(O₂) = n(NO₂)

Moles of each reactant:

n(N₂) = 5 mol

n(O₂) = 12 mol

Choose one reactant and determine how many moles of the other reactant are necessary to completely react with it. Let's choose N₂:

n(O₂) = 2 × n(N₂) = 2 × 5 mol = 10 mol

The calculation above means that we need 10 mol of O₂ to completely react with N₂.

We have 12 mol of O₂ and therefore more than enough oxygen gas.

Thus oxygen gas (O₂) is in excess and nitrogen gas (N₂) must be the limiting reagent.

Therefore,

n(NO₂) = 2 × n(N₂) = 2 × 5 mol = 10 mol

Moles of NO₂ = 10 mol

Answer: 10 mol of NO₂ are produced.