A stone weighing 2.0g absorbs 5.0J of heat and warms by 3.00C. What is the specific heat capacity of the stone?
q = m × C × ΔT
q = amount of heat energy gained or lost by substance (J)
m = mass of sample (g)
C = specific heat capacity of sample (J °C-1 g-1)
ΔT = change in temperature (°C)
(5.0 J) = (2.0 g) × C × (3.00°C)
С = (5.0 J) / (2.0 g × 3.00°C) = 0.833 J °C-1 g-1
C(stone) = 0.833 J °C-1 g-1
Answer: The specific heat capacity of the stone is 0.833 J °C-1 g-1.