Answer to Question #192778 in Chemistry for sadie

Question #192778

describe how you would prepare 465 mL of 0.3550 M potassium dichromate solution starting with solid potassium dichromate 


1
Expert's answer
2021-05-13T07:21:37-0400

CM = n / V

n = m / M

n (K2Cr2O7) = CM x V = 0.3550 x 0.465 = 0.165 mol

M (K2Cr2O7) = 294.185 g/mol

m (K2Cr2O7) = n x M = 0.165 x 294.185 = 48.56 g

To prepare 465 mL of 0.3550 M potassium dichromate solution weigth 48.56 g of K2Cr2O7.



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