Answer to Question #192778 in Chemistry for sadie

Question

describe how you would prepare 465 mL of 0.3550 M potassium dichromate solution starting with solid potassium dichromate 

Answer 1

C_M = n / V

n = m / M

n (K₂Cr₂O₇) = C_M x V = 0.3550 x 0.465 = 0.165 mol

M (K₂Cr₂O₇) = 294.185 g/mol

m (K₂Cr₂O₇) = n x M = 0.165 x 294.185 = 48.56 g

To prepare 465 mL of 0.3550 M potassium dichromate solution weigth 48.56 g of K₂Cr₂O_7.